A circular wire of radius 3 cm is cut and bent so as to lie along the circumference of a hoop whose radius is 48 cm find the angle in degrees which is subtended at the centre of hoop
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Circumference of wire of Radius 3 cm = 2π x 3 = 6π
Now because this wire is cut and placed along circle with a radius of 40 cm
PQ will be the length which will be acquired by this circle
it is known that the length of the arc is θ2πr/2π
now we will put the values in it
6π = θ2π x 40/2π
θ = 6π /40
θ = π/6.6 is the Answer
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first find ilthe circumference of both.then subract the smaller from the larger. now use the formula:-
l=the difference we calculated
r=48
thus we have all the values just substitute everything and lo!!! here we get the answer !!
l=the difference we calculated
r=48
thus we have all the values just substitute everything and lo!!! here we get the answer !!
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