A circular wire of radius 4.2 m is cut and bent in the form of a rectangle whose longer side is 20% more than its shorter side. The longer side of the rectangle is :
Answers
Answer:
7.1m
Step-by-step explanation:
Radius of circular wire= 4.2m
Circumference of circle= 2πr
2×22/7×4.2= 26.4m
The wire is bent in the form of rectangle
So, the perimeter of the rectangle= 26.4m
Let, Breadth= x
Length( longer side) = 20%+ x
L= 20/100+x
1/5+x= 5x+1/5 = x+1
Perimeter of the rectangle= 2(l+b)
26.4= 2(x+1+x)
26.4= 2(2x+1)
26.4= 4x+2
26.4-2= 4x
24.4= 4x
24.4/4 = x
6.1=x
Breadth= x= 6.1m
Length= x+1= 6.1+1
= 7.1 m
Given data,
radius of circular wire is
Let, smaller side of the rectangle is meters
given longer side is more than its shorter side, then
longer side of rectangle is
Now,
NOTE: even though the shape is changed. But, the perimeter is same because the length of wire is not changing.
Therefore, we can write
Perimeter of circle = Perimeter of the rectangle
if shorter side then the larger side will be
∴The longer side of the rectangle is
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