A circular wire of radius 42 cm is bent to form a square. find the ratio of their areas
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Answered by
1
Given,
Radius of the circle is r
Therefore, area of the circle =pi*r^2
Also,perimeter of the circle =2pi*r
Perimeter of the circle = perimeter of the square
Side of the square = 2pi*r/4
=pi*r/2
Area of the square =(pi*r/2)^2
=pi^2*r^2/4
Ratio=area of circle /area of square
=(pi*r^2)/(pi^2*r^2/4)
=4/pi
Hence, the ratio is 4/pi...
Sorry, if the answer seems a bit too clumsy.
Radius of the circle is r
Therefore, area of the circle =pi*r^2
Also,perimeter of the circle =2pi*r
Perimeter of the circle = perimeter of the square
Side of the square = 2pi*r/4
=pi*r/2
Area of the square =(pi*r/2)^2
=pi^2*r^2/4
Ratio=area of circle /area of square
=(pi*r^2)/(pi^2*r^2/4)
=4/pi
Hence, the ratio is 4/pi...
Sorry, if the answer seems a bit too clumsy.
Answered by
1
Radius of circle = 42cm
Perimeter of Square = 264 cm
[ as the same wire is bent into sq. ]
♦ Ratio of their areas = 11:14
Perimeter of Square = 264 cm
[ as the same wire is bent into sq. ]
♦ Ratio of their areas = 11:14
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