Question

 A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top f a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 30° .(see fig. 9.11)​

Answer 1

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Length of the rope is 20 m and angle made by the rope with the ground level is 30°.

Given:

 AC = 20 m and angle C = 30°

To Find:

Height of the pole

Let AB be the vertical pole

In right ΔABC,

using sine formula

sin 30° = AB/AC

Using value of sin 30 degrees is 1/2 , we have

1/2 = AB/20

AB= 20/2

AB= 10

Therefore,the height of the pole is 10m.

Answer 2

Given:-

• Rope length = 20m

• Angle made by rope with the ground level = 30°

To find:-

Height = ?

Solution:-

As we know that,

=>sinβ = $\frac{perpendicular}{hypotense}$

$= > \sin30 = \frac{height}{20} \\ = > \frac{1}{2} = \frac{height}{20} \\ = > heigth = \frac{20}{2} = 10m$

Hence the height will be 10m

Hope its help uh❤