Question

A circus artist is climbing a 20 m long rope, which is
tightly stretched and tied from the top of a vertical
pole to the ground. Find the height of the pole, if
the angle made by the rope with the ground level is
30°? ​

Answer 1

Step-by-step explanation:

Let AB be the vertical pole and CA be the rope.

Then,

Then,∠ACB=30° and AC=20 m

and AC=20 mIn right △ ABC,

sin30° = o = AC

AB

AB

AB

1 = 20

2 AB

AB

AB

AB AB=10 m

Therefore,the height of pole is 10m.

Answer 2

$\large{\sf{\orange{\underline{Answer ⇢}}}}$

➠ Height of pole = 10m

$\large{\sf{\blue{\underline{step~by~step~explanation⇢}}}}$

Let AB be the vertical pole and AC be the rope.

GiveN :

• Length of rope (AC) = 20m
• Angel made by the rope with the ground level (∠ACB=30) = 30°

To finD :

• Height of the pole (AB)

Solution :

We know that sin θ = $\small{\sf{\frac{side\: opposite\:to\: θ}{hypotension} }}$ or $\small{\sf{\frac{AB}{AC} }}$

Hence,

Sin30° = $\large{\sf{ \frac{AB }{AC} }}$

[ As we the value of sin30° = $\frac{1}{2}$

↦$\frac{1}{2}$ = $\frac{AB}{20}$

↦AB = $\frac{1}{2} \times 20$

↦$\large{\sf{\boxed{\green{AB = 10m}}}}$

Or,

$\large{\sf{\boxed{\green{Height\:of\:pole=10m}}}}$

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