Question

A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 30°. (see fig. 9.11)

Answer 1

$\huge{\underline{\underline{\underline{\sf{\pink{ﾑɳรᏇɛƦ \:࿐}}}}}}$

Length of the rope is 20 m and angle made by the rope with the ground level is 30°.

Given: AC = 20 m and angle C = 30°

To Find: Height of the pole

Let AB be the vertical pole

In right ΔABC, using sine formula

sin 30° = AB/AC

Using value of sin 30 degrees is ½, we have

1/2 = AB/20

AB = 20/2

AB = 10

Therefore, the height of the pole is 10 m.

Answer 2

Answer:

Height of pole = 10 m

Step-by-step explanation:

In this case,

sin theta = opposite / hypotenuse

=> sin 30 = opposite / hypotenuse

( hypotenuse = 20m ; opposite = x (pole height))

=> 1/2 = x / 20

=> 1/2 x 20 = x

=> 10 = x

Hence, x = height of pole = 10m