A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 30°. (see fig. 9.11)
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Answers
Answer:
10 m
Explanation:
Solution:
Length of the rope is 20 m and angle made by the rope with the ground level is 30°.
Given: AC = 20 m and angle C = 30°
To Find: Height of the pole
Let AB be the vertical pole
In right ∆ABC, using sine formula sin 30º = AB/AC
Using value of sin 30 degrees is 2, we have
1/2 = AB/20
AB = 20/2
AB = 10
Therefore, the height of the pole is 10 m.
❥ᴀɴsωᴇʀ ↴
⠀⠀⠀⠀⠀⠀⠀⠀⠀● AC = 20 m be the rope which the circus artist is climbing,
⠀⠀⠀⠀⠀⠀⠀⠀⠀● ∠ACB = 30°
⠀⠀⠀⠀⠀⠀⠀⠀⠀● In ΔABC, sin 30° = ABAC=h20ABAC=h20 ⇒ h20=12h20=12 ⇒ h = 1212 x 20m
⠀⠀⠀⠀⠀⠀⠀⠀⠀● = 10m
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