A circus artist is climbing a 20 m long rope which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole if the angle made by the rope with the ground level is 30degree
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Answer:
Let AB be the vertical pole and CA be the rope. Then,
∠ACB=30 and AC=20 m
In right △ ABC,
since 30 = AB/AC
1/2= AB/20
AB=10 M
Height of Poles Is 10M.
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Answered by
2
Let AB be the vertical pole and CA be the rope. Then,
∠ACB=30
o
and AC=20 m
In right △ ABC,
sin30
o
=
AC
AB
2
1
=
20
AB
AB=10 m
Therefore, the height of the pole is 10 m.
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