Question

A circus artist is climbing at 30m long rope,which is tightly stretched and tied from the top of a vertical pole to the ground.Find height of the pole, if the angle made by the rope with the ground is 45°.​

Answer 1

Answer:

I think, 15√2 m

here , sin45°=

$\frac{ab}{ac} = \frac{ab}{30} = \frac{1}{ \sqrt{2} }$

$ab = \frac{30}{ \sqrt{2} } = \frac{30}{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } = \frac{30 \sqrt{2} }{2} = 15 \sqrt{2}$

hence ,the height of pole is 15√2 m.

hope helps .

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