Question

a circus tent has a radius of 77 cm.A rope at the centre, of lenght 22 cm, is tied for the performance of artist. How much area is left for the audience

Answer 1

Given the radius of the tent us 77cm(R), the ring at the centre for the performance by artist have radius of 22cm(r).
Area left=area of outer circle-area of inner circle
=pi*R2-pi*r2
$(\pi \times {77}^{2} ) - (\pi \times {22) }^{2} \\ (\frac{22}{7} \times 77 \times 77) - ( \frac{22}{7} \times 22 \times 22) \\ \frac{22}{7} ( {77}^{2} - {22}^{2} ) \\ \frac{22}{7}(5929 - 484) \\ \frac{22}{7} (5445) \\ 22(777.85) \\ 17112.85 {cm}^{2}$

Answer 2

Answer:

17,112.85 CM²

Step-by-step explanation:

Radius of complete circus(r1) = 77Cm

Radius for performance area(r2) = 22Cm

Computation remain area :

$\pi (r1)^2 -\pi (r2)^2\\\pi [(r1)^2-(r2)^2]\\22/7[(77)^2-(22)^2]\\22/7[5,929 -484]\\22/7[5,445]\\22\times777.85\\=17,112.85cm^2$

Therefore, Area remain for audience = 17,112.85 CM²

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