Question

a circus tent is cylindrical to a height 4 m and conical above it. if it's diameter is 105 m and it's slant height is 40 m the total area of canvas required is:​

Answer 1

Given :-

• A circus tent is cylindrical to a height 4 m and conical above it. if it's diameter is 105 m and it's slant height is 40 m

To find :-

• Total area of canvas required

Solution :-

☆ Circus tent is in the form of cylinder and conical shape above on it. ☆

• Height of tent (h) = 4m
• Diameter of tent = 105m
• Radius of tent (r) = 105/2 = 52.5m
• Slant height of cone (l) = 40m

☆Now, total area of canvas required for tent

→ Curved surface area of cylinder + curved surface area of cone

→ 2πrh + πrl

☆Take πr as a common

→ πr(2h + l)

☆Substitute the value of height , radius and slant height

→ 22/7 × 52.5(2 × 4 + 40)

→ 22 × 7.5(8 + 40)

→ 165 × 48

→ 7920 m²

Hence,

• Total area of canvas required for tent is 7920m²

Extra Information :-

• Area of circle = πr² where " r " is radius

• Circumference of circle = 2πr

• Perimeter of rectangle = 2(l + b) where " l " is length and " b " is breadth

• Perimeter of square = 4 × a where " a " is side of the square

• Area of rhombus = ½ × product of diagonals

• Area of Parallelogram = b × h where " b " is base and " h " is height

Answer 2

Given:-

⠀

• a circus tent is cylindrical to a height 4 m and conical above it. if it's diameter is 105 m and it's slant height is 40 m.

⠀

To Find:-

⠀

• total area of canvas required

⠀

STEP BY STEP EXPLANATION:-

⠀

For the cylinder

⠀

The diameter will 105 m

⠀

Then radius is $\sf \frac{105}{2m}$

⠀

Now height is = 4m

⠀

For Cone

⠀

length = 80m and radius = $\sf \frac{105}{2}$

⠀

Total surface of the tent is sum of lateral surface of cone and cylinder

⠀

$\implies \sf2\pi rh + \pi rl$

⠀

$\sf \implies 1320 + 13200$

⠀

$\sf\implies14520 {m}^{2}$