Question

A circus tent is cylindrical to a height of 4 m and conical above it. If its diameter is 105 m and its slant height is 40 m, the total area of the canvas required in m² is
(a)1760
(b)2640
(c)3960
(d)7920

Answer 1

Answer:

The total area of the Canvas required is  7920 m².

Among the given options option (d) 7920 is the correct answer.

Step-by-step explanation:

Given :  

Diameter of cylinder and cone = 105 m  

Radius of cylinder and cone,r = 105/2 m = 52.5 m  

Height of a cylindrical part ,h = 4 m  

Slant height of a conical portion, l = 40 m

Total area of the Canvas required = curved surface area of cone + curved surface area of cylinder  

Total area of the Canvas required = πrl + 2πrh

= πr(l + 2h)

= 22/7 × 52.5 (40 + 2 × 4)

= 22 × 7.5 ×(40 + 8)

= 165 × 48

= 7920 m²

Total area of the Canvas required = 7920 m²

Hence, the total area of the Canvas required is  7920 m².

HOPE THIS ANSWER WILL HELP YOU….

Answer 2

$\mathfrak\pink{Solution}$

A circus tent is cylindrical to a height of 4 m and conical above it. If its diameter is 105 m and its slant height is 40 m, the total area of the canvas required in m² is

(a)1760

(b)2640

(c)3960

(d)7920

$\mathfrak\orange{Solution}$

$\bold{Diameter\:of \: cylinder=105\:m}$

$\bold{Radius}= \bold{\frac{105}{2}}$

$\bold{Height \:of \:the\: cylinder=4\:m$

Now,

$\bold{Length\:of\:cone=80\:m}$

$\bold{Radius}= \bold{\frac{105}{2}}$

Total Surface Area= Curved surface area of cylinder and cone

$= \bold{2\pi \: rh} + \bold{\pi \: rl}$

$= \bold{2 \times \frac{22}{7} \times \frac{105}{2} \times 4 + \frac{22}{7} + \frac{105}{2} + 80}$

$= \bold{7920}$

Therefore,

$\mathfrak\red{Option\:D\:is\:the\:answer}$