Question

A circus tent is cylindrical to a height of4m and conical above it if it's diameter is 105m and it's slant height is 40m find the total surface area of canvas required
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Answer 1

Answer:

For cylinder

Diameter is 105 m

then radius is 105/2 m

Now height=4 m

For cone

l=80 m and r=105/2

Tsa of the tent is the sum of lateral suface of cone and cylinder

=2πrh+πrl

=1320+13200

=14520 m²

Hope it helps...!

Answer 2

Solution :

$\bf{\large{\underline{\bf{Given\::}}}}}$

• A circus tent is cylindrical to a height = 4 m
• Diameter = 105 m
• Slant height = 40 m

$\bf{\large{\underline{\bf{To\:find\::}}}}}$

The total surface area of canvas.

$\bf{\large{\underline{\bf{Explanation\::}}}}}$

We have radius of conical = 105/2 m

We know that formula of the total surface area of canvas :

$\boxed{\bf{Area=2\pi rh+\pi rl}}}}}$

A/q

$\longrightarrow\tt{\bigg(2\times \dfrac{22}{\cancel{7}} \times \cancel{\dfrac{105}{2} }\times \cancel{4}\bigg)+\bigg(\cancel{\dfrac{22}{7}} \times \cancel{\dfrac{105}{2} }\times 40\bigg)}\\\\\\\longrightarrow\tt{(2\times 22\times 15\times 2)+(11\times 15\times 40)}\\\\\\\longrightarrow\tt{(44\times 30)+(11\times 600)}\\\\\\\longrightarrow\tt{(1320+6600)\:m^{2} }\\\\\\\longrightarrow\bf{7920\:m^{2} }$

Thus;

$\underbrace{\sf{The\:total\:surface\:area\:of\:canvas\:required\:will\:be\:\boxed{\bf{7920\:m^{2} }}}}}$