Question

A circus tent is cylindrical up to a height of 3 m and conical above it. If its diameter is 105 m and the slant height of the conical part is 63 m, then the total area of the canvas required to make the tent is

Answer 1

radius of cone =1052m=1052m

slant height of cone = 63 m

⇒⇒ Curved surface area of cone =(πrl)=(πrl)

=227×1052×63=10395m2=227×1052×63=10395m2

= Radius of culinder =1052m=1052m

Height = 3 m (given)

∴∴ Curved surface area of cylinder =2πrh=2πrh

=2×227×1052×3=990m2=2×227×1052×3=990m2

∴∴ Totall curved area of structure

⇒⇒ curved area of cone + curved area of cylinder

=10395+990=10395+990

=11385m2=11385m2

∴∴ Total area of canvas

=11385m2

Answer 2

h = 3m
d=105,r=105/2
l=63
TSA of canvas= CSA of cylinder +CSA of cone
Πrl+2Πrh
Πr (l+2h )
22/7×105/2(63+2(3))
22/7×105/2(63+6)
22/7×105/2×69
=11385cm sq.
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