Question

A circus tent is in the shape of a cylinder surmounted by a cone The diameter of the cylindrical portion is 24 m and height is 11 m.If the vertex of the cone is 16m above the ground,find the area of the canvas uesd to make the tent.

Answer 1

the area will be ar of cone+ ar of cylinder.

hope this help do calc. yourself please.

Answer 2

Answer:

The area of the canvas used to make the tent is 1320$\bold{\mathrm{m}^{2}}$

Step-by-step explanation:

Step 1:

Given Data:

Diameter of base of cylinder  is  d = 24 m

Radius of base of cylinder is r = d2 = 242 = 12 m

Step 2:

Height of cylinder, h = 11 m

Total height of the tent = 16 m  

h1 = 16 − 11 = 5 m Radius of base of conical portion,

Step 3:

r = 12 m

Slant height of cone, $\bold{L=\sqrt{r^{2}+h^{2}}}$

$=\sqrt{12^{2}+5^{2}}$ = √ 144+25 = √169= 13 m

Step 4:

Area  of canvas  = CSA of cylinder + CSA of cone

=2πrh + πrl=πr[2h+l]

=227×12×(22+13)

Step 5:

=227×12×35  

= 60×22  

= 1320$\mathrm{m}^{2}$