Question

A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:

A) 49 B) 50 C) 53.5 D) 55

Answer 1

Answer:

(A) part 49

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Answer 2

Step-by-step explanation:

ANSWER

Consider it as a cuboid of length =6m, width =4m & height =1.25m

What we have to calculate is ( total surface area of cuboid -surface area of top).

Since water will be wetting the surface in contact & these surfaces area the four walls & the bottom

surface area of walls =a+b+c+d

6×1.25+6×1.25+4×1.25+4×125=25m

Surface area of bottom =6×4=24m

total area of water surface =25+24=43m

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