Question

A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:

A) 49
B) 50
C) 53.5
D) 55

Answer 1

Answer:

A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is: 49

OPTION : A) 49

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GOOD NIGHT ❤️❤️.

Answer 2

Answer:

$\huge\mathrm{Answer}$

$\implies$

$49m {}^{2}$

Consider it as a cuboid of length =6m, width =4m & height =1.25m

Consider it as a cuboid of length =6m, width =4m & height =1.25m What we have to calculate is ( total surface area of cuboid -surface area of top).

Consider it as a cuboid of length =6m, width =4m & height =1.25m What we have to calculate is ( total surface area of cuboid -surface area of top).Since water will be wetting the surface in contact & these surfaces area the four walls & the bottom

Surface area of walls= a+ b+ c+ d

= 6×1.25 + 6×1.25 + 4×1.25 + 4× 1.25 = 25m2

Surface area of bottom =6×4=

$24m {}^{2}$

total area of water surface =25+24=

$43m {}^{2}$