Question

a cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. the total area of the wet surface is:

Answer 1

$here \: is \: your \: \: answer$

↪length = 6m

↪ breadth = 4m

so using the formula ,

↪Area of the wet surface,

= [2(lb + bh + lh) - lb] 

= 2(bh + lh) + lb 

= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4]m^2  

= 49m^2.
$the \: total \: area \: of \: the \: wet \: surface \: is \: = 49 {m}^{2}$


$hope \: it \: helps$


$\beta e \: \beta \gamma \alpha inly$

Answer 2

Hi dear here is your answer.