Math, asked by pashupatimura7143, 10 months ago

A cistern can be filled by 2 pipes a and b in 10 and 15 hrs respectively is then emptied by a tap in 8 hrs. If all the tap are opened the cistern will be filled in?

Answers

Answered by srikrishnakumarrvs
0

Answer:

24 hours

Step-by-step explanation:

a=1/10

b=1/15

empty=1/8

all together = 1/10 + 1/15 - 1/8 = (12+8-15)/120 = 5/120 = 1/24

total 24 hours

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