Math, asked by mehnuma, 1 year ago

A cistern can be filled by 3 taps A,B&C when turned on separrtely in12min,10min &15min respectively .If all are turned on togerher for8/3min &if B &C are then turned off ,how much time will A alone take to fill the cistern?​

Answers

Answered by TheLostMonk
2

Answer:

4mins

Step-by-step explanation:

capacity= LCM(12,10,15) = 60 units

A,B,& C does = (5,6,4 )units/min

all 3 together does = 15units/min

filled in 8/3min = 8/3 *15 = 40 units

R = 20 units

A will fill the r.cistern in 20/5=4 min

Similar questions