a cistern can be filled by one tap 8 hours,and by another jn12 hours.if both are openef together in the empty tank,how much time will they take to fill it completely?lesson name is problems on time and work aswer is a 4 hours . solution in step by step.
Answers
Answered by
2
Take lcm of 8 12 =24
Capacity of tank =24
So capacity of first tap=24/8=3
Capacity of sec tap=24/12=2
So time take to fill the tank=
24/5=4.8
So ans is 4hrs 48min (.8*60=48min)
Capacity of tank =24
So capacity of first tap=24/8=3
Capacity of sec tap=24/12=2
So time take to fill the tank=
24/5=4.8
So ans is 4hrs 48min (.8*60=48min)
thandapani:
thanks
Similar questions