A cistern can be filled by pipes a and b in 2 hours and 3 hours respectively. when full, the tank can be emptied by a pipe c in 6 hrs. if all the taps be turned on at the same time, in what time will the cistern be full
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Let the tank capacity be x
Rate of inflow due to A =x/2 hours
Rate of inflow due to B=x/3 hours
Rate of outflow due to C=x/6 so
Total rate of inflow =x/2+x/3+(-x/6)=4x/6
Time taken = x/(4x/6)=6/4=3/2 hours
Rate of inflow due to A =x/2 hours
Rate of inflow due to B=x/3 hours
Rate of outflow due to C=x/6 so
Total rate of inflow =x/2+x/3+(-x/6)=4x/6
Time taken = x/(4x/6)=6/4=3/2 hours
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