Question

A cistern can be filled by two taps A and B in 12 hours and 16 hours
respectively. The full cistern can be emptied by a third tap C in 8 hours. If
all the taps are opened at the same time, in how much time will the empty
cistern be filed completely?​

Answer 1

Answer:

48 hrs

Step-by-step explanation:

let volume of tank = T

in 1 hr

Tank A fills --- T/12

Tank B fills --- T/16

Tank C empties --- T/8

thus, in 1 hr tank fills = (T/12)+(T/16)-(T/8) = (T/48)

thus, tank will require 48 hrs to fill with tap A, B and C all open

Answer 2

Answer:

48 hours

Step-by-step explanation:

A can fill 1/ 12 of cistern in 1 hour

B can fill 1/16 of cistern in 1 hour

C can empty 1/8 of cistern in 1 hour