A cistern can be filled by two taps A and B in 12 hours and 16 hours, respectively. The full cistern can be emptied by a third tap in 8 hours. If all the taps are opened at the same time, in how much time will the empty cistern be filled up completely?
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Answered by
1
Answer:
28 hours 29 hours of work filled complete
Answered by
3
Answer:
tap A to fill the cistern = 12 hours.
tap B to fill the cistern = 16 hours.
tap C to empty the full cistern = 8 hours.
A’s 1 hour’s work = ¹/₁₂
B’s 1 hour’s work = ¹/₁₆
C’s 1 hour’s work = −1/9 (cistern being emptied by C)
(A + B + C)’s 1 hours net work= (¹/₁₂ + ¹/₁₆ - ¹/₈) = ¹/₄₈
time taken by (A + B + C) to fill the cistern = 48 hours.
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