Question

A cistern can be filled by two taps A and B in 12 hours and 6 hours respectively. The full cistern can be emptied by a third tap C in 8 hours. If all the taps are turned on at the same time, in how much time will the empty cistern be filled up completely?​

Answer 1

Answer:

first tap=1/12 work in one hour

second tap=1/6 work in one hour

third tap=-1/8 work in one hour

1/12+1/6-1/8=2/24+4/24-3/24

6/24-3/24=3/24=1/8=8 hours

Answer 2

Answer:

please mark brainliest