A cistern contains 50 litres of water. 5 litres of water is taken out of it and replaced by wine. the process is repeated again. find the proportion of wine and water in the resulting mixture
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Answered by
5
total watar 50 litres
then we take out 5 litre water
and mix 5 litre wine
so we have 50 litres mixture of water &wine
we repeat this process
then watar 45- 4=41
wine is5-1=4
and 4+5=9
so
mixture=watàr+wine
50=41+9
so
watàr/wine=41/9
then we take out 5 litre water
and mix 5 litre wine
so we have 50 litres mixture of water &wine
we repeat this process
then watar 45- 4=41
wine is5-1=4
and 4+5=9
so
mixture=watàr+wine
50=41+9
so
watàr/wine=41/9
naveen706:
am i right
Answered by
22
5 ltr of 50ltr 10%
therefore wine is 10% CONC. ( 5LTR wine)
the conc remains same even if you remove excess mixture.
youll hv 45ltr mixture i.e 4.5 ltr wine(10%) . add 5 ltr wine.
so total 9.5 ltr wine and 40.5 ltr water.
9.5::40.5
19::81
this is the ans.
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