Math, asked by zero3641, 11 months ago

A cistern has two inlets A and B which can fill it in 21 minutes and28 minutes respectively. An outlet C can empty the full cistern in 14 minutes. If all the three pipes are opened together in the empty tank. In how much time will they fill the cistern?

Answers

Answered by kalyaniprasad8
0

Answer:

Step-by-step explanation:

A can fill the cistern in 21 mins.

Thus it fills 1/21 of the cistern in 1 min.

B can fill the cistern in 28 mins.

Thus it fills 1/28 of the cistern in 1 min.

C can empty the cistern in 14 mins.

It can empty 1/14 of the cistern in 1 min

Thus, in 1 min

1/21+1/28-1/14 cistern is filled

1/21-1/28 cistern is filled

1/7(1/3-1/4) cistern is filled

1/7*1/12 cistern is filled

1/84 cistern is filled

Therefore, the cistern is filled in 1/1/84 mins=84 mins or 1 hr 24 mins

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