Question

A cistern has two supply pipes A,B and a waste pipe C. Through A and B, the cistern can be filled in 15 minutes and 18 minutes respectively. Through C the full cistern can be emptied in 20 minutes. At first the pipes A and C are opened for 5 minutes. Then the pipe A is closed and the pipe B is opened. How much time is needed to fill the cistern?????




step by step explanation needed


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Answer 1

Answer:

Let the 3 taps be A, B and C.

A fills tank in 12 mins -> In 1 min A will fill 1/12 of tank.

B fills tank in 15 mins -> In 1 min B will fill 1/15 of tank.

Lets say C can alone empty the tank in x mins -> In 1 min C will empty 1/x of tank.

According to question, if all taps are opened tank will fill in 20 mins.

In each min 1/20 tank is filled which is due to A, B and C. Now A and B fill the tank will C empty the tank.

1/12 + 1/15 - 1/x = 1/20

1/12 + 1/15 - 1/20 = 1/x

(5+4-3)/60 = 1/x

6/60 = 1/x

x = 10

Step-by-step explanation:

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Answer 2

Answer:

wholesaler sold an article to a dealer for ₹80,000. the dealer then sells the article to a shopkeeper at a profit of ₹15,000. if the rate of gst is 12% and all the sales are intra-state, find : (i) the price inclusive of tax (under gst) at which the shopkeeper bought the article. (ii) the tax (under gst) paid by the dealer to the state government. (iii) the tax (under gst) received by the central government.