Math, asked by Michelle15, 1 year ago

a cistern internally measuring 150cm×120×110 has 129600cm3 of water porous bricks are placed in it until cistern is full to the brim each brick absorbs one seventeenth of its on volume of water how many bricks can be put with each brick being 22.5cm×7.5×6.5

Answers

Answered by MrPerfect0007
136
Volume of cistern = 150cm x 120cm x 110cm = 1980000 cm3
Volume of water = 129600 cm3
Volume of brick = 22.5cm x 7.5cm x 6.5cm =1096.875 cm3
Volume of water absorbed by the brick =1/17(Volume of brick) =64.52 cm3
Now let x bricks can be put in the cistern = 1096.875x
So volume of water displayed by x bricks = 64.52 x
Change in the volume of water after dropping the bricks = 129600 - 1096.875x -64.52 x
Water will not overflow if above volume = 1980000
129600 +1096.875x -64.52 x=1980000
Solving we get
1032.355x= 1787400
X = 1731.381162
So 1731 bricks are required
Answered by piyushbd28
163

Hi there here's your answer

Hope it helps

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