A cistern, internally measuring 150cm×120cm×110cm, has 129600cm cube of water in it. Porous bricks are placed in water until the cistern is full to the brim. Each brick absorb one-seventeenth of its own volume of water .How many bricks can be put in without overflowing the water, each brick being 22.5cm×7.5cm×6.5cm?
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Volume of cistern = 150cm x 120cm x 110cm = 1980000 cm3
Volume of water = 129600 cm3
Volume of brick = 22.5cm x 7.5cm x 6.5cm =1096.875 cm3
Volume of water absorbed by the brick =1/17(Volume of brick) =64.52 cm3
Now let x bricks can be put in the cistern = 1096.875x
So volume of water displayed by x bricks = 64.52 x
Change in the volume of water after dropping the bricks = 129600 - 1096.875x -64.52 x
Water will not overflow if above volume = 1980000
129600 +1096.875x -64.52 x=1980000
Solving we get
1032.355x= 1787400
X = 1731.381162
So 1731 bricks are required
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