Math, asked by mansipattnaik, 1 year ago

A cistern, internally measuring 150cm×120cm×110cm, has 129600cm cube of water in it. Porous bricks are placed in water until the cistern is full to the brim. Each brick absorb one-seventeenth of its own volume of water .How many bricks can be put in without overflowing the water, each brick being 22.5cm×7.5cm×6.5cm?

Answer plz


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Answers

Answered by Anonymous
5

Volume of cistern = 150cm x 120cm x 110cm = 1980000 cm3

Volume of water = 129600 cm3

Volume of brick = 22.5cm x 7.5cm x 6.5cm =1096.875 cm3

Volume of water absorbed by the brick =1/17(Volume of brick) =64.52 cm3

Now let x bricks can be put in the cistern = 1096.875x

So volume of water displayed by x bricks = 64.52 x

Change in the volume of water after dropping the bricks = 129600 - 1096.875x -64.52 x

Water will not overflow if above volume = 1980000

129600 +1096.875x -64.52 x=1980000

Solving we get

1032.355x= 1787400

X = 1731.381162

So 1731 bricks are required



Anonymous: Pleasure !
Answered by Anonymous
3
HEY Buddy.......!! here is ur answer

I hope it will be helpful for you....!!

THANK YOU ✌️✌️
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