A cistern is provided with 2 pipes A and B . A can fill it in 20 minutes and B can empty it in 30 minutes.If A and B be kept open alternatively for one minute each, how soon will the cistern be filled
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total work = 60( LCM of 20 and 30)
work of A in 1 min=60/20=3
work of B in 1 min =60/30=2
total work in 2 mins =5
total work will be completed in 60/5= 12 mins
work of A in 1 min=60/20=3
work of B in 1 min =60/30=2
total work in 2 mins =5
total work will be completed in 60/5= 12 mins
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