Question

A city bus is carrying 70 passengers ,some with 50 paise ticket and the remaining with 1rupee tickets.if the total amount recieved by the conductor was rupees 56. Find the number of passengers of each type.

Answer 1

Answer:

50 paise ticket passenger is 28

1 Rs. ticket passenger is 42

Step-by-step explanation:

Let,

The number of passengers with 50 paise ticket = x

The number of passengers with Rs. 1 ticket = 70 - x

Recieved total amount = Rs. 56

50p. (x)

⇒ 0.5x

1 Rs. (70 - x )

⇒ 70 - x

★ According to the question

⇒ 0.5x + 70 - x = 56

⇒ 0.5x + 70 - x = 56

⇒ 0.5x - x = 56 - 70

⇒ - 0.5x = - 14

⇒ 0.5x = 14

⇒ x = 14 / 0.5

⇒ x = 28

The number of passengers with 50 paise ticket = 28

The number of passengers with Rs. 1 ticket = 70 - x

⇒ 70 - 28

⇒ 42

The number of passengers with Rs. 1 ticket = 42

Therefore,

50 paise ticket passenger is 28

1 Rs. ticket passenger is 42

Answer 2

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Solution:

Let the number of passengers that were

charged 50 paise be 'x' and the passengers

that were charged Rs. 1 be 70 - x.

Total amount received Rs. 56

Therefore, according to the question

0.5x+(7O -x)1 = 565

0.5x+ 70 - x = 56

0.5x - x = 56 - 70

- 0.5x = - 14

X = 14/0.5

X 28

28 passengers were charged 50 paise.

And, the number of passengers who were

charged Rs. 1 were 70 28 42.