Question

A city bus is carrying 70 passengers,some with50 paisetickets and the remaining with 1 rupee tickets. if tthe total amount recieved by the conductor was 56 ,find the number of passengers of each type

Answer 1

Answer:

28 and 42

Step-by-step explanation:

let the two types of passengers be x and y

where type x passenger takes Rs. 0.50 ticket

and type y passenger takes Rs. 1 ticket

total number of passengers = 70

x + y = 70 equation (1)

total amount collected by conductor = 56

0.50x + 1y = 56 equation (2)

subtract equation (1) - (2)

x + y - (0.50x + y) = 70 - 56

x + y - 0.50x - y = 14

0.50x = 14

x = 14 / 0.50

x = 28

substitute x = 28 in equation (1)

x + y = 70

28 + y = 70

y = 70 - 28

y = 42

therefore number of passengers with 0.50 paise tickets are 28

number of passengers with Rs. 1 tickets are 42

Hope you get your answer