A city had 3,00,000 people. The population of the city grew by 3% in the first year, by 2 1/2% in the 2nd year and
by 2 1/4% in the 3rd year. Find out the city's population at the end of 3 years.
please answer with procedure properly
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Answers
Step-by-step explanation:
Given : P=2,00,000
Population after first year
=2,00,000(1+
100
10
)
1
=2,00,000(
100
110
)=2,20,000
Principal for the second year =2,20,000
Population at the end of second year
=2,20,000[1+
100
15
]
1
=2,20,000×
100
115
=2,53,000
Answer:
323250 people
Step-by-step explanation:
Population of the city = 300000
Increase in population in the city = 3%
3% of 300000 = 300000 / 100
= 3000 per 1%
= 3% = 3000 * 3
= 9000 people in the first year
Increase in population in second year = 2.5%
2.5% of 300000 = 300000 / 100
= 3000 per 1%
= 2.5% = 3000 * 2.5
= 7500 people in second year
Increase in population in third year = 2.25%
2.25% of 30000 = 300000 / 100
= 3000 per 1%
= 2.25% = 3000 * 2.25
= 6750 people in third year
Total population = 300000 + 9000 + 7500 + 6750
= 323250