Math, asked by nehaagarwal0899, 3 months ago



A city water supply tank has two inlet pipes X and Y, which can fill it in 20 and 30 hours respectively, and an
outlet pipe Z which can empty a full tank in 40 hours. If the tank is empty and the taps are opened in
succession for one hour each, and the process continues, in how many hours will the tank get filled?

Answers

Answered by DhanurRelhan
68

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17 hours and one-seventh of an hour

REFER TO THE ATTACHMENT

A lil Bit Justification For Your Understanding :—

They Collectively have to fill the tank. 2 pipes are doing work in the same direction and the third is opposing them. So, this tells us that the sign of 2 pipes will be different from the other two {Difference is Absolute so we can take any of those two faction to be negative or positive}. they are performing one action so the sum of the work potential shall be equal to 1 (or -1 as I took just for ease) and we know time taken is inversely proportional to work potential. So that's all u need to know to solve (•‿•)

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Attachments:
Answered by oshinaantony12
47

Answer:

the answer is 49 1/2

Step-by-step explanation:

answer is 49 1/2

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