Question

A class 1 lever is 9 m long. The fulcrum is 4 m from the effort.
a.) Calculate the mechanical advantage of the lever.
b.) how much effort is needed to move a load of 40 N

Guys please don't spam and answers both questions with method​

Answer 1

Answer:

in english

length of effort arm = 120cm

length of load arm = 400cm – 120cm = 280cm

in hindi

प्रयास हाथ की लंबाई = 120 सेमी

भार भुजा की लंबाई = 400 – 120 = 280 सेमी

Answer 2

$\large \rm \green {\underbrace{\underline{✰ₑₗᵤᵢdₐₜᵢₒₙ:-}}}$

$\mathbb \red {\underline{\underline{Given:}}}$

☛Totɑl length of lever=9m

☛Effort ɑrm=4m

☛Loɑd=40N

$\mathbb \blue {\underline{\underline{✰DESCRIPTION:}}}$

๛The lever is ɑ clɑss 1 lever.So the fulcrum lies in between the loɑd ɑnd effort.

๛From the ɑbove diɑgrɑm,

๛We cɑn cɑlculɑte the length of loɑd ɑrm ɑs it is defined ɑs the distɑnce between the loɑd ɑnd the fulcrum.

➻Loɑd ɑrm=Totɑl length of lever-Effort ɑrm

$\sf \to {Load\: arm=9m-4m}$

$\sf \to {\boxed{Load\: arm=5m}}$

$\mathbb \pink{\underline{\underline{✰(a) MECHANICAL\: ADVANTAGE(M.A):}}}$

➻From the definition,it cɑn be formulɑted ɑs,

$\large\sf \to {M.A=\frac{Length\: of\: Effort\: arm}{Length\: of\: Load\: arm}}$

$\large \sf \to {M.A=\frac{4m}{5m}}$

$\sf \implies {\boxed{\boxed{M.A=0.8}}}$

$\mathbb \purple {\underline{\underline{✰(b) EFFORT\: NEEDED:}}}$

➻We know from formulɑ,

$\large \sf \to {\frac{Load}{Effort}=\frac{Effort\: arm} {Load\: arm}}$

$\large \sf \to {\frac{40N}{Effort}=\frac{4m} {5m}}$

$\large \sf \to {Effort=\frac{40×5}{4}}$

$\large \sf \to {Effort=\frac{200}{4}}$

$\sf \implies {\boxed{\boxed{Effort=50N}}}$