A class A transformer coupled transistor power amplifier is required to deliver a power output of 10 watts. The maximum power rating of the transistor should not less than (a) 3W (b) 10W (c) 20 W
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Answer:
(b)10 W
Explanation:
Given output power i.e., Pac = 10 W
Power dissipated across transistor, PQ = Pdc - Pac
Efficiency, ղ = Pac / Pdc
For a fixed Pac, the input power Pdc is minimum for maximum value of ղ.
Now, ղmax = 50% or 0.5 for class-A transformer coupled power amplifier.
Thus, minimum dissipated power across transistor,
PQ (min) = Pdc(min) - Pac = (Pac / ղmax) - Pac = (10/0.5) – 10 = 10
Thus, PQ (min) = 10 W
Transistor maximum power rating should be greater than or equal to PQ (min).
So, maximum power rating of the transistor should not be less than 10 W.
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