Question

a class board contains 64 equal squares is 6.25 cm² A border round around the board is 3 cm the discriminant of the quadratic equation formed in this case is​

Answer 1

Answer:

The length of the side of the chess board be 24 cm.

Step-by-step explanation:

Let the length of the side of the chess board be x cm. Then,

Area of 64 squares = (x−4)²

Therefore,

(x−4)² = 64 × 6.25

x² −8x + 16 = 400

x² −8x − 384 = 0

x² −24x + 16x − 384 = 0

(x−24) (x+16) = 0

x = 24 cm

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