Question

A class consist of a number of boys whose ages
are in A.P., the common difference being 4
months. If the youngest boy is just 8 years old
and the sum of their ages is 168 years, then find
the number of boys in the class.​

Answer 1

Step-by-step explanation:

Let us first convert all years in months.

8yrs=96 month, 168yrs=2016 months.

Now, a=96

s=2016

d=4

n=?

s=n/2(2a+(n-1)d)

2016=n/2(192+(n-1)4)

4032=n(192+4n-4)

4032=4n2+188n

4n2+188n-4032=0

n²+47n-1008=0

n²+63n-16n-1008=0

n(n+63)-16(n+63)=0

(n-16)(n+63)=0

n=16 and n=-63

Therefore the numbers of students=16,

(we neglatected -63 as numbers of students cannot be negative)

Answer 2

Values are wrong answer is not possible

Plz check the values of the question then ask