Question

a class consists of a number of boys whose ages are in AP the common difference being 4 months if the youngest boys is 8 years and if the sum of Ages is 168 years then the number of boys is​

Answer 1

A=8×12 MONTHS=96 MOTHS

D=4 MONTHS

168=A +(N-1)D

168=4 +( N-1)4

164=(N-1)4

164/4=(N-1)

41=N-1

42=N

THEREFORE NUMBER OF BOYS IS 42.