A class has 32 pupils at present.This represents2/3 of the original number of pupulis in the class.How many pupils were originally in the class?A.48 B.16 C.50 D.40
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present pupils =32
from problem present pupils are the 2/3 of the the original number of pupils on the class
then
assume total number of pupils in class =X
so 2X/3 = 32
X = 32×3÷2
X = 16×3
X=48
therefore pupils originally in the class = 48
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