A class has 6 boys and 7 girls,, out of them they have to select group of 6 students for performing a mime,
so that the selected group should have at least 4 girls.
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- As the question asks about at least one boy should be selected, so from total no. of ways of selecting 4 children subtract none of the boys which gives us one boys + 2 boys + 3 boys + 4 boys, which is our required answer at least one boys. So the answer is C(10,4)-C(4,4)=209. C(10,4) is no. of ways of selecting 4 children's from 6 boys and 4 girls. C(4,4) is no. of ways of selecting 4 girls from 4 girls which is 1 way. So the answer is 209.
- In the second method let’s select 1 boy, 3 girls + 2 boys, 2 girls + 3 boys, 1 girl + 4 boys which is C(6,1)*C(4,3) + C(6,2)* C(4,2) + C(6,3)* C(4,1)+ C(6,4)= 209. In both ways answer is 209.
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