A class is composed of two brothers and six other boys. In how many ways can all the boys be seated at a round table so that the two brothers are not seated beside each other?
Answers
Answered by
2
Answer:
1/4 is the correct answer I think so most probably
Answered by
13
Answer:
3600 is the answer... .....
Step-by-step explanation:
Take 1 person from 6 and fix him and 5 others can arranged in -- 5! ways=120
there are 6 places left in which 2 brothers can sit
so they can choose any 2 places from 6 - 6C2 ways=15
2 brothers can arrange themselves in 2! ways=15*2=30
total ways=120*30=3600
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