a. Class marks of a continuous uniform distribution are 4, 10, 16, 22 and 28. The difference between upper limit of last class interval and lower limit of first class interval is equal to:
b. The mean of x,(x^2+1) and (5x-2) is 5 then mean of x, 2x and 3x is equal to(x>0).
c.The mean of marks of 8 students is 35. If one student is removed from this group then mean becomes 32 then marks of the student who is removed is equal to:
Answers
Answer:
1.) upper limit=28
lower limit = 4
classmark= 28-4= 24
Given : Class marks of a continuous uniform distribution are 4, 10, 16, 22 and 28.
To Find : The difference between upper limit of last class interval and lower limit of first class interval is equal to:
Solution:
Class marks of a continuous uniform distribution are 4, 10, 16, 22 and 28.
Difference between class marks = 6
6/2 = 3
Add and subtract 3 in Class marks to create class interval
4 - 3 , 4 + 3 => 1 - 7
Similarly other
1 - 7
7 - 13
13 - 19
19 - 25
25 - 31
upper limit of last class interval = 31
lower limit of first class interval = 1
Difference = 31 - 1 = 30
The mean of x,(x²+1) and (5x-2) is 5
=> x + x² + 1 + 5x - 2 = 3 * 5
=> x² + 6x - 16 = 0
=> (x + 8)(x - 2) = 0
x = 2 as x > 0
mean of x, 2x and 3x
= (x + 2x + 3x)/3
= 2x
= 2 (2)
= 4
mean of marks of 8 students is 35.
Total Marks = 8 * 35 = 280
one student is removed from this group then mean becomes 32
=> 7 * 32 = 224
Mark of removed student = 280 - 224 = 56
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