Math, asked by kashvisriva9, 22 hours ago

a. Class marks of a continuous uniform distribution are 4, 10, 16, 22 and 28. The difference between upper limit of last class interval and lower limit of first class interval is equal to:

b. The mean of x,(x^2+1) and (5x-2) is 5 then mean of x, 2x and 3x is equal to(x>0).

c.The mean of marks of 8 students is 35. If one student is removed from this group then mean becomes 32 then marks of the student who is removed is equal to:

Answers

Answered by adityakakran
1

Answer:

1.) upper limit=28

lower limit = 4

classmark= 28-4= 24

Answered by amitnrw
0

Given : Class marks of a continuous uniform distribution are 4, 10, 16, 22 and 28.

To Find : The difference between upper limit of last class interval and lower limit of first class interval is equal to:

Solution:

Class marks of a continuous uniform distribution are 4, 10, 16, 22 and 28.

Difference between class marks = 6

6/2 = 3

Add and subtract 3 in Class marks to create class interval

4 - 3   , 4 +  3   => 1  - 7

Similarly other

1 -  7

7 - 13

13 - 19

19 - 25

25 - 31

upper limit of last class interval  = 31

lower limit of first class interval = 1

Difference = 31  - 1  = 30

The mean of x,(x²+1) and (5x-2) is 5

=> x + x² + 1 + 5x - 2  = 3 * 5

=> x² + 6x  - 16 = 0

=> (x + 8)(x - 2) = 0

x = 2    as x > 0

mean of x, 2x and 3x  

= (x + 2x + 3x)/3

= 2x

= 2 (2)

= 4

mean of marks of 8 students is 35.

Total Marks = 8 * 35  = 280

one student is removed from this group then mean becomes 32

=> 7 * 32  =  224

Mark of removed student = 280 - 224  = 56

Learn More:

Arithmetic mean of nine observation is calculated as 38 . But in ...

brainly.in/question/8318092

43 the average income of a group of 50 persons working in a factory ...

brainly.in/question/11635184

Similar questions