A class teacher has the following attendance record of 40 students of a class for the whole term find the mean number of days a student was present out of 56 days in the term number of days 35-38 38-41 41-44 44-47 47-50 50-53 52-56 number of students 1 3 4 4 7 10 11
Answers
Hey Dear,
● Answer -
Mean = 49 days
◆ Explanation -
For this we have to calculate fi.xi for each class.
For class 35-38,
fixi = 36.5 × 1
fixi = 36.5
For class 38-41,
fixi = 39.5 × 3
fixi = 118.5
For class 41-44,
fixi = 42.5 × 4
fixi = 170
For class 44-47,
fixi = 45.5 × 4
fixi = 182
For class 47-50,
fixi = 48.5 × 7
fixi = 339.5
For class 50-53,
fixi = 51.5 × 10
fixi = 515
For class 53-56,
fixi = 54.5 × 11
fixi = 599.5
Summation fixi will be -
Σfixi = 36.5 + 118.5 + 170 + 182 + 339.5 + 515 + 599.5
Σfixi = 1961
Mean no of days each student attended school will be -
Mean = Σfixi / Σfi
Mean = 1961 / 40
Mean = 49.05 days
Therefore, mean no of days a student was present in school is 49 days.
Best luck...
Given : A class teacher has the following attendance record of 40 students of a class for the whole team.
Complete Data is:
35-38 38-41 41-44 44-47 47-50 50-53 53-56
1 3 4 4 7 10 11
To Find : the mean number of days a student was present out of 56 days
Solution:
A = Assume mean = 48.5 , h = 3
Days f Mean u =(Mean - A)/3 fu
35-38 1 36.5 -4 -4
38-41 3 39.5 -3 -9
41-44 4 42.5 -2 -8
44-47 4 45.5 -1 -4
47-50 7 48.5 0 0
50-53 10 51.5 1 10
53-56 11 54.5 2 22
Total 40 7
48.5 + 3 * 7 / 40
= 48.5 + 0.525
= 49.025
mean number of days a student was present out of 56 days = 49.025
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