A classroom 11 m long, 8 m wide and 5 m high. Find the sum of the areas of its floor and the four walls.
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Answer:
278 cm²
Step-by-step explanation:
Length of room = 11 m
Breadth of room = 8 m
Height of room = 5 m
∴ Floor Area = l × b
= 11 × 8 m²
= 88 m²
Area of the four walls = 2h(l+b)
= 2 × 5(11 + 8)
= 10 × 19
= 190 m²
∴ Area of the floor + Area of four walls
⇒88 + 190 m²
⇒278 m²
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