Question

A classroom is 11m long 8 meters wide and 5.5m high. find the sum of the areas of the four walls and its floor

Answer 1

Hi friend✋✋✋✋
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Your answer
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Length of a classroom = 11 m

Breadth of the classroom = 8m

Height of the classroom = 5.5 m

Area of its four walls = Lateral surface area

= 2(l + b)h

= [2 × (11 + 8) × 5.5] m²

= [ 11 × 19] m²

= 209 m²

Now,
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Area of the floor = length × breadth

= (11 × 8) m²

= 88 m²

So,
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Sum of the area of four walls of the room and the floor = (209 + 88) m² = 297 m²

HOPE IT HELPS

Answer 2

Answer:

Answer is 397 m^2

Step-by-step explanation:

Surface area of a classroom= 2(lb+ bh+ lb)-(lb)

= 2( 11×8+8×5.5+5.5×11) - (11×8)

= 2(192.5) - 88

= 386 -88

= 397 m^2