A classroom is 11m long 8 meters wide and 5.5m high. find the sum of the areas of the four walls and its floor
Answers
Answered by
74
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Your answer
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Length of a classroom = 11 m
Breadth of the classroom = 8m
Height of the classroom = 5.5 m
Area of its four walls = Lateral surface area
= 2(l + b)h
= [2 × (11 + 8) × 5.5] m²
= [ 11 × 19] m²
= 209 m²
Now,
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Area of the floor = length × breadth
= (11 × 8) m²
= 88 m²
So,
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Sum of the area of four walls of the room and the floor = (209 + 88) m² = 297 m²
HOPE IT HELPS
---------------
Your answer
--------------------
Length of a classroom = 11 m
Breadth of the classroom = 8m
Height of the classroom = 5.5 m
Area of its four walls = Lateral surface area
= 2(l + b)h
= [2 × (11 + 8) × 5.5] m²
= [ 11 × 19] m²
= 209 m²
Now,
--------
Area of the floor = length × breadth
= (11 × 8) m²
= 88 m²
So,
------
Sum of the area of four walls of the room and the floor = (209 + 88) m² = 297 m²
HOPE IT HELPS
Answered by
3
Answer:
Answer is 397 m^2
Step-by-step explanation:
Surface area of a classroom= 2(lb+ bh+ lb)-(lb)
= 2( 11×8+8×5.5+5.5×11) - (11×8)
= 2(192.5) - 88
= 386 -88
= 397 m^2
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