Question

A clock clicks 88 times in 22 seconds. Calculate the frequency and period of the clockA clock clicks 88 times in 22 seconds. Calculate the frequency and period of the clock

Answer 1

Answer:

1) The frequency of the clock is 4 Hz

2) The period of the clock is 0.25 s

Explanation:

1)

In a periodic motion, the frequency of the motion is equal to the number of complete cycles per second.

Mathematically:

f=\frac{N}{t}f=

t

N

f is the frequency

N is the number of cycles completed in a time t

For the clock in this problem, we have

N = 88 (number of cycles)

t = 22 s (time interval)

Substituting,

f=\frac{88}{22}=4 Hzf=

22

88

=4Hz

2)

The period of a periodic motion is the time taken for one complete oscillation to occur.

Mathematically, the period is equivalent to the reciprocal of the frequency:

T=\frac{1}{f}T=

f

1

where

T is the period

f is the frequency

Here we have found

f = 4 Hz

So, the period of the clock is

T=\frac{1}{4}=0.25 sT=

4

1

=0.25s

Explanation:

mark me a brainlist and follow for more answers