Question

A clock has a minute-hand 10 cm long. Find the average
velocity between 6.00 AM to 6.30 AM for the tip of
minute-hand.​

Answer 1

Explanation:

Length of minute hand r=10cm

In 30 minutes, the tip of minute hand reaches diametrically opposite end of the clock.

Thus displacement of tip of minute hand d=2r=10 cm

Time taken t=30 min=30×60=1800 s

So, average velocity =d÷t = 20÷1800

=0.011 cm/s