A clock loses 2 minutes in a hour and another clock gains 2 minutes in every 2 hours. Both these clocks are set correctly at a certain time on Sunday and both the clock stop simultaneously on the next day with the time shown being 9 am and 10 : 06 AM. What is the correct time at which they stopped ?
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Answer:
9 : 44 am
Step-by-step explanation:
Speed of 1 st clock =58min/hr
Speed of 2nd clock =61min/hr [Since it
gains 2min in 2hrs, it should gain 1min in 1hr]
Relative velocity of 2ndclock wrt 1st
=61−58=3min/hr
Relative distance travelled by the 2nd clock wrt 1st by the time both are stopped =1hr6min=66min
Time taken by the 2nd clock wrt 1st to cover 66min=66/3=22hours
In those 22 hours, mins covered by the 1st
clock =22×58=1276
The actual mins elapsed in those 22hours=22×60=1320
∴ Number of mins the 1st
clcok is behind the correct time=1320−1276=44mins
⇒ If the time on the 1st
clock is 9am, then the correct time is 9:44am
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